# How many numbers are there between 100 and 1000 such that?

## How many numbers are there between 100 and 1000 such that?

Now the required value can be obtained by subtracting the calculated value from a number of numbers between \$ 100 \$ and \$ 1000 \$. We have \$ 1000-100=900 \$ numbers between \$ 100 \$ and \$ 1000 \$ .

### How many numbers are there between 99 and 1000 having at least?

7 is in the unit’s place. The middle digit can be any one of the 10 digits from 0 to 9. The digit in hundred’s place can be any one of the 9 digits from 1 to 9. Therefore by the fundamental principle of counting there are 10 × 9 = 90 numbers between 99 and 1000 having 7 in the unit’s place.

#### How many numbers between 100 and 600 have a 3 for at least one of the digits?

176 numbers
Look Back There are 176 numbers between 100 and 600 that have a 3 for at least one of the digits.

How many digits are there between 100 and 1000 which have exactly one of their digits as 7?

Hence, the numbers between 100 and 1000 having the digit 7 exactly once are 72 + 72 + 81 = 225.

How many numbers are there between 100 and 1000 at least one of their digits is 6?

225 numbers
The count of numbers between 100 and 100 which have exactly one digit as 6 is the sum of the numbers having 6 at hundreds place, the numbers having 6 at ten’s place, and the numbers having 6 at unit’s place. numbers. Thus, there are 225 numbers between 100 and 1000 that have exactly one of the digits as 6.

## How many numbers are there between 100 and 1000 such that exactly one of their digits is 5?

Third, three-digit numbers having three 5s: There is (1*1*1) = 1 such number. So, the answer will be (225 + 26 + 1) = 252. Therefore, there are 252 numbers between 100 and 1000 such that they have 5 as at least one of the digits.

### How many numbers are there between 100 and 1000 which have exactly one of their digits as 5?

Hence, the number of numbers between 100 and 1000 is 225. The option (B) is the correct option.

#### How many numbers are there between 100 and 1000 such that every digit is either 3 or 4?

Now we will use the fact that numbers should have only 2 and 9 as their digits, so we will find all the possible arrangements that can be done using these conditions and that will be the final answer. Then the only possible number is 222.

How many numbers are there between 100 and 999 inclusive such that at least one of their digits is 5?

There are 10 numbers with the first and third digit equal to 5. There are 9 numbers with the second and third digit equal to 5. There are 8x9x9 = 648 numbers with no digit equal to 5.

How many numbers are there between 100 and 999 inclusive such that at least one of their digits is 1?

The total no. of numbers are: 9 * 9 * 8 = 648. Cheers! You can choose any digit one to nine inclusive for the first digit, for a total of nine choices.