How many 4 digit numbers are there that are divisible by 5?

How many 4 digit numbers are there that are divisible by 5?

answer it 120 four digit numbers can be formed.

What is the greatest 4 digit number divisible by 5?

9999/5 will be 1999 with a remainder of 4.

How many of these numbers are divisible by 5?

A number is divisible by 5 if its units place is 0 or 5. Consider the following numbers which are divisible by 5, using the test of divisibility by 5: 50, 75, 90, 165, 120. In 50, the unit’s place digit is 0. Hence, 50 is divisible by 5.

How many 4 digit numbers are there which are divisible by 2?

Thus there are 4999 – 500 + 1 = 4500 , 4 – digit numbers divisible by 2 .

How many 4 digits numbers are there divisible by 9?

Here is the original problem: There are 9000 distinct 4-digit positive integers. If we add restrictions to the make up of the numbers, then the number of possible 4-digit numbers may be reduced.

What is the greatest 4 digit number divisible by 4?

9999
Aptitude :: Numbers – Discussion Explanation: Largest 4-digit number = 9999 88) 9999 (113 88 —- 119 88 —- 319 264 — 55 — Required number = (9999 – 55) = 9944.

What is the greatest 4 digit number exactly divisible by 5/12 15?

∴ The largest four-digit number exactly divisible by 12, 15, 20, and 35 is 9660.

How do you get divisible by 5?

The divisibility rule of 5 states that if the digit on the units place, that is, the last digit of a given number is 5 or 0, then such a number is divisible by 5. For example, in 39865, the last digit is 5, hence, the number is completely divisible by 5.

Which pair of numbers is divisible by 5?

Answer: Five pairs of Prime Numbers less than 20 whose sum is divisible by 5 are (2,3), (3,7), (2,13), (5,5), (3,17), (7,13) According to the Divisibility Rule of 5, any number ending with 0 or 5 is divisible by 5.

How many 4 digit numbers each divisible by 4 can be formed?

For a number to be divisible by 4, the last two digits of the number have to be 56, 76, 96, 68 or 88. The first two digits of these numbers can be filled in 5 x 5 = 25 ways (numbers can be repeated). Hence, in total there are 25 x 5 = 125 such numbers.

How many 4 digit numbers can be formed from the digits 12345 which are divisible by 3?

Hence the units place can be filled in ‘2’ ways. Therefore, the number of 4 digited numbers divisible by 3. =63×2=216×2=432.