# How many 5-digit numbers can be formed from the?

Table of Contents

- 1 How many 5-digit numbers can be formed from the?
- 2 How many 5-digit numbers can be made from the digits 1 2 3 4 so that all the digits are taken in each number?
- 3 How many 5 digit numbers can be created such that no digit is repeated?
- 4 How many 5 digit zip codes are there?
- 5 How many 5 digit numbers can be formed from 12345 How many of them are even?
- 6 How many 5 digit numbers can be formed using 0 9 without repeating?
- 7 How do you find the place value of a 5 digit number?
- 8 What is the total number of combinations possible with 5 numbers?

## How many 5-digit numbers can be formed from the?

Repetition of digits is allowed. ∴ Each place out of unit, 10th, 100th and 1000th can be filled in 5 ways. Total numbers =4×5×5×5×5=2500.

### How many 5-digit numbers can be made from the digits 1 2 3 4 so that all the digits are taken in each number?

Therefore, each digit of a 5-digit number so formed is one of [1, 2, 3, 4] = 4 choices, with repetition. Therefore, the number of 5-digit numbers possible is: 4*4*4*4*4 = 1024.

**How many 5-digit combinations are there using 0 5?**

If you choose to not count any combination of 5 digits starting with a leading 0, then the first 5-digit number is 10,000 and the last 5-digit number is 99,999. That gives you 90,000 5-digit numbers. In that case the general formula would be 9*10 N-1 for the number of possible N-digit numbers.

**How many 5 digit numbers can be formed using 1/9 if no digit can appear more than twice?**

The answer is 7,560 five-digit numbers.

## How many 5 digit numbers can be created such that no digit is repeated?

No digit is ever repeated for 10⋅9⋅8⋅7⋅6=30240 numbers. The total number of 5 digit numbers is 105=100000.

### How many 5 digit zip codes are there?

1 Expert Answer There are ten possible digits (0 to 9). This means 100000 possible zip codes if repeatable.

**How many 5 digit numbers can be formed with the digits 9876543210?**

a) Consider 9876543210. You need to choose five of these digits to make your number. There are thus (105)=252 options.

**How many 5 digit numbers can be formed using odd digits?**

49999 – 5000 + 1 = 45,000. There are 45000 even five digit numbers. There are 5 odd digits, so there are 5 ways to choose each digit, and the number of five digit numbers composed of only odd digits is 5^5 = 3125.

## How many 5 digit numbers can be formed from 12345 How many of them are even?

ways = 120 ways.

### How many 5 digit numbers can be formed using 0 9 without repeating?

Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number. The total number of 5 digit numbers have no digits repeated is 9x9x8x7x6 which is equal to 27216. You can use whatever digits you wish except 0 for X1. The answer remains the same.

**How many possible 5-digit numbers are there?**

The smallest 5 5 -digit number is 10000, 10000, while the largest 5 5 -digit number is 99999. 99999. These 90000 90000 possible 5 5 -digit numbers can have any number from 0 0 to 9 9 in any of the places, except for the placement of zero such that there is no non-zero number to its left.

**Can the digit at the ten thousand place in a number?**

The digit at the ten thousand place in a 5-digit number can never be 0. Example 1: Find the sum and difference of the greatest 5-digit number and the smallest 5-digit number. The greatest 5-digit number is 99,999. The smallest 5-digit number is 10,000.

## How do you find the place value of a 5 digit number?

The place value of the five digits that make up the 5-digit number would be obtained by progressively multiplying the respective figure by 1, 10, 100, 1,000, and 10,000 starting from the rightmost digit and moving to the left. As shown above, is a 5-digit number, every progressive place value is the earlier place value multiplied by 10.

### What is the total number of combinations possible with 5 numbers?

Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways. Therefore, the total number of combinations possible are 10 × 10 × 10 × 10 × 10 = 1,00,000.